Example 1: Input: prices = [7,1,5,3,6,4] … Contribute to yznpku/HackerRank development by creating an account on GitHub. HackerRank - Stock Maximize Your algorithms have become so good at predicting the market that you now know what the share price of Wooden Orange Toothpicks Inc. (WOT) will be for the next N days. Plot3D doesn't generate the ellipitic paraboloid it's supposed to. of row ) times. Making statements based on opinion; back them up with references or personal experience. Is there a dynamic programming solution ? Sell all the stocks on that day and split the array after that day and recurse on the remaining elements .MathJax_SVG_Display {text-align: center; margin: 1em 0em; position: relative; display: block!important; text-indent: 0; max-width: none; max-height: none; min-width: 0; min-height: 0; width: 100%} .MathJax_SVG .MJX-monospace {font-family: monospace} .MathJax_SVG .MJX-sans-serif {font-family: sans-serif} .MathJax_SVG {display: inline; font-style: normal; font-weight: normal; line-height: normal; font-size: 100%; font-size-adjust: none; text-indent: Hackerrank Breadth First Search: Shortest Reach Solution. j > i for a i in linear access. b) If that day is the last day then quit: else: Arrays. But the catch is, from a particular village i, you can only move to a village j if and only if \(i < j\) and the profit gain from village j is a multiple of the profit gain from village i. You are given a function f(X)=X^2. So my question is can anyone think of a more efficient solution to this problem ? Given a 2D array arr[][] with each row of the form {l, r}, the task is to find a pair (i, j) such that the… Read More. Your algorithms have become so good at predicting the market that can predict the share price of Wooden Orange Toothpicks Inc. 0.Start from end of array so that no need to recurse To learn more, see our tips on writing great answers. Just explain how you do for each a[i] find a[j] s.t. Over the course of the next few (actually many) days, I will be posting the solutions to previous Hacker Rank challenges. site design / logo © 2021 Stack Exchange Inc; user contributions licensed under cc by-sa. Note that you need to take exactly one element from each list, not necessarily the largest element. You add the squares of the chosen elements and perform the modulo operation. so, the Best you can do for a price at a[i] is Buy at a[i] and Sell at a[j]. Worked alone for the same company during 7 years, now I feel like I lack a lot of basics skills, Finding the 8 outer corner vertices of an object, Short story: invention of a device to view the past, Short story about survivors on Earth after the atmosphere has frozen. // pre-process the stock price array and find the days on which we should // sell the shares for maximum profit: boolean [] sellOn = findSellingDays(stockPrices, days); long totalCost = 0, totalProfit = 0; int numShares = 0; // go through all the array containing stock prices and do … Maximizing profit for given stock quotes (6) . is the max() function necessary while summing up the profit? Competitive Programming. P.S: this is the first time i am asking a question here. The list consists of elements. Is there any meaningful difference between event.getParam("x") and event.getParams().x? We also need to look at previous best local min (C# implementation). In theory, this problem is listed under "dynamic programming" what is exactly has to do with dynamic programming here? Orientation of a cylindrical habitat/ship in transit. a) highest stock price on day 2 .. so we buy stock on day 1 and sell it on day 2 ( profit = 3 ) then we recurse on the remaining days : 1 2 3, b) Max price is 3 ( on day 5) so we keep buying stock on day 3 and day 4 and sell on day 5 ( profit = ( 3*2 - 3 = 3 ), The complexity for this turns out to be O(n^2) .